Re: its ugly but getting there... twin-charged SRT-6!!!
Originally Posted by Thumper SRT6
Just some corrections to the math:
14PSI boost is a pressure ratio of 1.95 --> (14 + 14.7) / 14.7
So PR1 from the turbo (1.95) compounded with the PR2 of the supercharger (1.95) is 1.95*1.95 = 3.80
Boost gauge will read:
BG = (PR1*PR2 - 1)*14.7
BG = (3.80 - 1) * 14.7 = 41.16 PSIG
This equation derived from the Pressure Ratio equation, then solving for Bgauge:
PR = (Bgauge + 14.7) / 14.7
PR * 14.7 = Bgauge + 14.7
PR*14.7 - 14.7 = Bgauge
(
PR - 1)*14.7 = Bgauge
Thanks Thumper was rushing writing the post but i just trying to explain that its not a simple as turbo psi+supercharger psi when your compounding through a supercharger
edited original post
Last edited by ProjectMayhem; Jul 19, 2010 at 12:10 AM.