Re: What happens when you wash an Intercooler ?? Eh Bunkey?
I have not done the math but lets work it out. . . .
3.2 liters x 6000 RPM DIVIDE by 2 ( 4 stroke motor: i.e. 2 revs per displacement ) = 9600 liters per minute.
1 cubic foot = 28.3 liters.
9600 liters / min. /// 28.3 liters / cfm= 339 cfm.
Given an SRT-6 motor under full throttle boost at "JUST" 14.7 PSIG boost = 2x the engine cfm demanded = 678 cfm near-abouts or as engineers say thats a WAG.
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The 4 - 5 inches of water pressure drop in the IC, due to crud ( restriction )
1 inAq ≈ .036 psi, or 27.7 inAq ≈ 1 psi.
therefore 4.5 ( the average pressure change ) x 0.036 = 0.162 psi drop.
Assuming ( beware of that term ) Atmosphere = 14.7 psig @ sea level
Therefore 0.162 psig / 14.7 psig = 0.011 normalized OR ABOUT 1.1% pressure loss : MEASURED at 1/3 on nominal engine flow ( see above 678 cfm ). My shop vac was about 250 cfm, which means that a dirty Innercooler costs you from 1.1% on the low side up to about 5% given the greater ( actual engine air flow of 678 cfm ) rate of air moving thru the innercooler.
1% is the change due to a cooler inlet temperature ( IAT ) of about 10 degrees 2+ to 4 H/P
5% is a difference that will kick your buttt 10 to 20 HP.
This gives you the range to anticipate 2 to 20 HP depending on the math, restriction of the intercooler, and test equipment.
I GOTTA GET A BIGGER SHOP VAC !!!!! ROB - please test the new IC and your dirty one to show us the difference ( again ) for comparison.
Woody ENJOY>
WAG = wild *** guess
BTW the water side was clean it seemed, I chemically cleaned the whole thing as I have to do some rework to and fix the leaks, video needs to be made up, next week.
Just wanted to figure cfm at 17PSIG boost;
14.7 + 17 / 14.7 = 31.7 / 14.7 =
= boost of 2.156 x times 339 CFM of unboosted motor or 731 cfm.
Last edited by waldig; Nov 7, 2012 at 04:14 PM.